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NEW QUESTION # 37
View the Exhibit and examine the details of PRODUCT_INFORMATION table.
You have the requirement to display PRODUCT_NAME from the table where the CATEGORY_ID column has values 12 or 13, and the SUPPLIER_ID column has the value 102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?
- A. It would execute and the output would display the desired result.
- B. It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.
- C. It would execute but the output would return no rows.
- D. It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.
Answer: C
NEW QUESTION # 38
Evaluate the following CREATE TABLE command:
Which statement is true regarding the above SQL statement?
- A. It would execute successfully and two indexes ORD_ITM_IDX and ORD_ITM_ID PK would be created.
- B. It would give an error because the USING INDEX is not permitted in the CRETAE TABLE command.
- C. It would give an error because the USING INDEX clause cannot be used on a composite primary.
- D. It would execute successfully and only ORD_ITM_IDX index would be created.
Answer: D
NEW QUESTION # 39
Examine the description of the MEMBERStable:
Examine the partial query:
SELECT city, last_name LNAME FROM members ...;
You want to display all cities that contain the string AN. The cities must be returned in ascending order, with the last names further sorted in descending order.
Which two clauses must you add to the query? (Choose two.)
- A. WHERE city IN ('%AN%')
- B. WHERE city LIKE '%AN%'
- C. ORDER BY last_name DESC, city ASC
- D. ORDER BY 1, 2
- E. WHERE city = '%AN%'
- F. ORDER BY 1, LNAME DESC
Answer: C,F
Explanation:
Explanation/Reference: https://www.techonthenet.com/sql/order_by.php
https://www.studytonight.com/dbms/orderby-clause.php
NEW QUESTION # 40
Examine the data in the PRODUCTS table:
Examine these queries:
1. SELECT prod name, prod list
FROM products
WHERE prod 1ist NOT IN(1020) AND category _id=1;
2. SELECT prod name, | prod _ list
FROM products
WHERE prod list < > ANY (1020) AND category _id= 1;
SELECT prod name, prod _ list
FROM products
WHERE prod_ list <> ALL (10 20) AND category _ id= 1;
Which queries generate the same output?
- A. 1 and 3
- B. 2 and 3
- C. 1 and 2
- D. 1, 2 and 3
Answer: A
Explanation:
Based on the given PRODUCTS table and the SQL queries provided:
* Query 1: Excludes rows where prod_list is 10 or 20 and category_id is 1.
* Query 2: Includes rows where prod_list is neither 10 nor 20 and category_id is 1.
* Query 3: Excludes rows where prod_list is both 10 and 20 (which is not possible for a single value) and category_id is 1.
The correct answer is A, queries 1 and 3 will produce the same result. Both queries exclude rows where prod_list is 10 or 20 and include only rows from category_id 1. The NOT IN operator excludes the values within the list, and <> ALL operator ensures that prod_list is not equal to any of the values in the list, which effectively excludes the same set of rows.
Query 2, using the <> ANY operator, is incorrect because this operator will return true if prod_list is different from any of the values in the list, which is not the logic represented by the other two queries.
NEW QUESTION # 41
Examine these SQL statements which execute successfully:
Which two statements are true after execution? (Choose two.)
- A. The foreign key constraint will be enabled and IMMEDIATE.
- B. The foreign key constraint will be enabled and DEFERRED.
- C. The primary key constraint will be enabled and DEFERRED.
- D. The primary key constraint will be enabled and IMMEDIATE.
- E. The foreign key constraint will be disabled.
Answer: D,E
NEW QUESTION # 42
Examine the structure of the CUSTOMERS table: (Choose two.)
CUSTNO is the PRIMARY KEY.
You must determine if any customers' details have been entered more than once using a different CUSTNO, by listing all duplicate names.
Which two methods can you use to get the required result?
- A. Self-join
- B. Subquery
- C. Full outer-join with self-join
- D. Right outer-join with self-join
- E. Left outer-join with self-join
Answer: A,B
NEW QUESTION # 43
Examine this partial statement:
Which is true?
- A. The query can select only zero rows or one row, but the subquery can select any number of rows.
- B. Both the query and the subquery can select any number of rows.
- C. Both the query and the subquery can select only zero rows or one row.
- D. The query can select any number of rows, but the subquery can select only zero rows or one row.
Answer: A
Explanation:
Explanation/Reference: http://dcx.sybase.com/1200/en/dbusage/ug-subquery-s-4318996.html
NEW QUESTION # 44
Which three statements are true regarding indexes? (Choose three.)
- A. A UNIQUE index can be altered to be non-unique
- B. When a table is dropped and is moved to the RECYCLE BIN, all indexes built on that table are permanently dropped
- C. An update to a table can result in no updates to any of the table's indexes
- D. A table belonging to one user can have an index that belongs to a different user
- E. An update to a table can result in updates to any or all of the table's indexes
- F. A SELECT statement can access one or more indices without accessing any tables
Answer: B,C,F
NEW QUESTION # 45
The SALES table has columns PROD_IDand QUANTITY_SOLDof data type NUMBER.
Which two queries execute successfully? (Choose two.)
- A. BY prod_id HAVING COUNT(*) >10;
SELECT COUNT (prod_id) FROM sales WHERE quantity_sold > 55000 GROUP BY - B. SELECT prod_id FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id HAVING
- C. COUNT(*) >10;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP - D. prod_id;
SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP - E. BY COUNT(*) >10;
SELECT COUNT(prod_id) FROM sales GROUP BY prod_id WHERE quantity_sold > 55000;
Answer: A,B
NEW QUESTION # 46
Which three statements are true? (Choose three.)
- A. The USER_CONS_COLUMNSview should be queried to find the names of columns to which constraints apply.
- B. The usernames of all the users including database administrators are stored in the data dictionary.
- C. Views with the same name but different prefixes, such as DBA, ALLand USER, reference the same base tables from the data dictionary.
- D. The data dictionary views consist of joins of dictionary base tables and user-defined tables.
- E. Both USER_OBJECTSand CATviews provide the same information about all objects that are owned by the user.
- F. The data dictionary is created and maintained by the database administrator.
Answer: A,B,C
Explanation:
Explanation
Explanation/Reference:
References:
https://docs.oracle.com/cd/B10501_01/server.920/a96524/c05dicti.htm
NEW QUESTION # 47
View the Exhibit and examine the structure of the ORDERS table. (Choose the best answer.)
You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?
- A. SELECT order_id, order_date FROM ordersWHERE order_date > ANY(SELECT order_date FROM orders WHERE customer_id = 101);
- B. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT order_date FROM orders WHERE customer_id = 101);
- C. SELECT order_id, order_date FROM ordersWHERE order_date > ALL(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;
- D. SELECT order_id, order_date FROM ordersWHERE order_date > IN(SELECT order_date FROM orders WHERE customer_id = 101);
Answer: B
NEW QUESTION # 48
In the PROMOTIONS table, the PROMO_BEGIN_DATE column is of data type DATE and the default date format is DD-MON-RR.
Which two statements are true about expressions using PROMO_BEGIN_DATE contained a query?
- A. TO_NUMBER(PROMO_BEGIN_DATE) - 5 will return a number.
- B. PROMO_BEGIN_DATE - SYSDATE will return a number.
- C. PROMO_BEGIN_DATE - SYSDATE will return an error.
- D. PROMO_BEGIN_DATE - 5 will return a date.
- E. TO_DATE(PROMO_BEGIN_DATE * 5) will return a date.
Answer: D,E
NEW QUESTION # 49
Which normal form is a table in if it has no multi-valued attributes and no partial dependencies?
- A. Fourth normal form
- B. Third normal form
- C. First normal form
- D. Second normal form
Answer: D
NEW QUESTION # 50
Examine these requirements:
1. Display book titles for books purchased before January 17, 2007 costing less than 500 or more than 1000.
2. Sort the titles by date of purchase, starting with the most recently purchased book.
Which two queries can be used?
- A. SELECT book_title FROM books WHERE (price NOT BETWEEN 500 AND 1000) AND (purchase_date< '17-JAN-2007') ORDER BY purchase_date DESC;
- B. SELECT book_title FROM books WHERE (price< 500 OR >1000) AND (purchase date<
'17-JAN-2007') ORDER BY purchase date DESC; - C. SELECT book_title FROM books WHERE (price IN (500, 1000)) AND (purchase date <
'17-JAN-2007') ORDER BY purchase_date ASC; - D. SELECT book_title FROM books WHERE (price BETWEEN 500 AND 1000) AND
(purchase_date<'17-JAN-2007') ORDER BY purchase_date;
Answer: A,B
NEW QUESTION # 51
Examine the structure of the SALES table. (Choose two.)
Examine this statement:
SQL > CREATE TABLE sales1 (prod_id, cust_id, quantity_sold, price)
AS
SELECT product_id, customer_id, quantity_sold, price
FROM sales
WHERE 1 = 2;
Which two statements are true about the SALES1 table?
- A. It will not be created because of the invalid WHERE clause.
- B. It is created with no rows.
- C. It has PRIMARY KEY and UNIQUE constraints on the selected columns which had those constraints in the SALES table.
- D. It will have NOT NULL constraints on the selected columns which had those constraints in the SALES table.
- E. It will not be created because the column-specified names in the SELECT and CREATE TABLE clauses do not match.
Answer: B,D
NEW QUESTION # 52
Examine the structure of the EMPLOYEES table.
NameNull?Type
---------------------- ------------
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
EMAILNOT NULLVARCHAR2(25)
PHONE NUMBERVARCHAR2(20)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(8,2)
COMMISSION_PCTNUMBER(2,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
- A. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
- B. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
- C. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
- D. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
Answer: B
NEW QUESTION # 53
You want to write a query that prompts for two column names and the WHERE condition each time It is executed in a session but only prompts for the table name the first time it is executed. The variables used in your query are never undefined in your session . Which query can be used?
- A. SELECT &col1, &col2
FROM "&table"
WHERE &condition; - B. SELECT &&col1,&&col2
FROM &table
WHERE &&condition= &&cond; - C. SELECT'&co11','&&co12'
FROM &table
WHERE'&&condition' ='&cond'; - D. SELECT &col1, &col2
FROM &&table
WHERE &condition; - E. SELECT&&col1, &&col2
FROM &table
WHERE &&condition;
Answer: D
NEW QUESTION # 54
Examine the commands used to create DEPARTMENT_DETAILS and
COURSE_DETAILS tables:
You want to generate a list of all department IDs that do not exist in the COURSE_DETAILS table.
You execute the SQL statement:
What is the outcome?
- A. It executes successfully and displays the required list.
- B. It fails because the ON clause condition is not valid.
- C. It executes successfully but displays an incorrect list.
- D. It fails because the join type used is incorrect.
Answer: A
NEW QUESTION # 55
Examine this SELECT statement and view the Exhibit to see its output: (Choose two.) SELECT constraints_name, constraints_type, search_condition, r_constraints_name, delete_rule, status, FROM user_constraints WHERE table_name = 'ORDERS'; Which two statements are true about the output?
- A. In the second column, 'c' indicates a check constraint.
- B. The DELETE_RULE column indicates the desired state of related rows in the child table when the corresponding row is deleted from the parent table.
- C. The STATUS column indicates whether the table is currently in use.
- D. The R_CONSTRAINT_NAME column contains an alternative name for the constraint.
Answer: A,B
NEW QUESTION # 56
Which statement is true regarding the INTERSECToperator?
- A. Reversing the order of the intersected tables alters the result.
- B. The names of columns in all SELECTstatements must be identical.
- C. The number of columns and data types must be identical for all SELECTstatements in the query.
- D. It ignores NULLvalues.
Answer: D
NEW QUESTION # 57
Examine this SQL statement:
SELECT cust_id, cus_last_name "Last Name"
FROM customers
WHERE country_id = 10
UNION
SELECT cust_id CUST_NO, cust_last_name
FROM customers
WHERE country_id = 30
Identify three ORDER BY clauses, any one of which can complete the query successfully.
- A. ORDER BY 2,cust_id
- B. ORDER BY CUST_NO
- C. ORDER BY "Last Name"
- D. ORDER BY "CUST_NO"
- E. ORDERBY 2, 1
Answer: C,E
Explanation:
In SQL, the ORDER BY clause can refer to columns by their alias defined in the SELECT clause or by their positional number in the SELECT list. It's important to understand that after a UNION, the column names in the ORDER BY clause refer to the first SELECT statement's column names and aliases:
* Option A: ORDER BY 2, 1This is correct because it refers to the second and first columns in the first SELECT clause, which correspond to the aliases "Last Name" and cust_id, respectively.
* Option E: ORDER BY "Last Name"This is correct because "Last Name" is a valid alias defined in the first SELECT clause.
The other options fail for the following reasons:
* Option B: "CUST_NO" is not recognized in the ORDER BY clause because it's not an alias used in the first SELECT statement.
* Option C: Incorrect because 2, cust_id mixes positional reference with a column name that doesn't apply to both SELECT statements consistently.
* Option D: ORDER BY CUST_NO fails because CUST_NO is not an alias in the first SELECT clause.
NEW QUESTION # 58
Examine the description of the CUSTOMERS table:
You want to display details of all customers who reside in cities starting with the letter D followed by at least two character.
Which query can be used?
- A. SELECT * FROM customers WHERE city LIKE'D %';
- B. SELECT * FROM customers WHERE city ='%D_';
- C. SELECT * FROM customers WHERE city LIKE'D_';
- D. SELECT * FROM customers WHERE city ='D_%';
Answer: D
Explanation:
The LIKE operator is used in SQL to search for a specified pattern in a column. To find all customers residing in cities starting with 'D' followed by at least two characters, you need to use the LIKE operator with the appropriate wildcard pattern:
A . SELECT * FROM customers WHERE city LIKE 'D_%'; The underscore () wildcard character in SQL represents a single character. The percent (%) wildcard character represents zero or more characters. So 'D%' will match any city starting with 'D' followed by at least one character (as there is one underscore).
Reference:
Oracle Database SQL Language Reference 12c, specifically the section on pattern matching with the LIKE condition.
NEW QUESTION # 59
Examine this partial command:
Which two clauses are required for this command to execute successfully?
- A. the access driver TYPE clause
- B. the DEFAULT DIRECTORY clause
- C. the ACCESS PARAMETERS clause
- D. the REJECT LIMIT clause
- E. the LOCATION clause
Answer: B,E
NEW QUESTION # 60
Which three statements are true regarding group functions? (Choose three.)
- A. They can be used only on one column in the SELECT clause.
- B. They can be used with a SQL statement that has a GROUP BY clause.
- C. They can be passed as an argument to another group function.
- D. They can be used together with the single-row functions in the SELECT clause.
- E. They can be used on columns or expressions.
Answer: C,D,E
Explanation:
Explanation
References:
https://www.safaribooksonline.com/library/view/mastering-oracle-sql/0596006322/ch04.html
NEW QUESTION # 61
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