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Oracle 1Z0-007 Exam Syllabus Topics:

Oracle Introduction to Oracle9i: SQL Sample Questions:

Question 1

Evaluate these two SQL statements:
SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER BY salary DESC; SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER BY 2 DESC; What is true about them?

A. The second statement returns a syntax error.
B. There is no need to specify DESC because the results are sorted in descending order by default.
C. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.
D. The two statements produce identical results.

Question 2

You need to display the last names of those employees who have the letter "A" as the second character in their names.
Which SQL statement displays the required results?

A. SELECT last_name FROM EMP WHERE last_name LIKE '_A%';
B. SELECT last_name FROM EMP WHERE last name LIKE '*A%'
C. SELECT last_name FROM EMP WHERE last name ='_A%';
D. SELECT last_name FROM EMP WHERE last name ='*A%'

Question 3

You need to change the definition of an existing table. The COMMERCIALS table needs its DESCRIPTION column changed to hold varying length characters up to 2000 bytes. The column can currently hold 1000 bytes per value. The table contains 20000 rows.
Which statement is valid?

A. ALTER TABLE commercials
CHANGE (description CHAR2(2000));
B. ALTER TABLE commercials
MODIFY (description CHAR2(2000));
C. You cannot increase the size of a column if the table has rows.
D. ALTER TABLE commercials
CHANGE (description VARCHAR2(2000));
E. ALTER TABLE commercials
MODIFY (description VARCHAR2(2000));

Question 4

Examine the data in the EMPLOYEES and EMP_HIST tables:

The EMP_HIST table is updated at the end of every year. The employee ID, name, job ID, and salary of each existing employee are modified with the latest data. New employee details are added to the table.
Which statement accomplishes this task?

A. MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE emp hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employee_id, e.name, e.job_id, e.salary);
B. MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT VALUES (e.employee id, e.name,
C. UPDATE emp_hist SET employee_id, name, job_id, salary = (SELECT employee_id, name, job_id, salary FROM employees) WHERE employee_id IN (SELECT employee_id FROM employees);
D. MERGE INTO emp_hist eh USING employees e WHEN MATCHED THEN UPDATE emp_hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employee_id, e.name, e.job_id, e.salary);
E. job id, e.salary);

Question 5

Evaluate the SQL statement:
SELECT ROUND(45.953, -1), TRUNC(45.936, 2)
FROM dual;
Which values are displayed?

A. 50 and 45.9
B. 50 and 45.93
C. 46 and 45
D. 46 and 45.93
E. 45.95 and 45.93
F. 45 and 45.93

Solutions: